18JUL21
SOLVING LINEAR EQUATIONS IN TWO VARIABLES
Example 1:
x+y=5
x-y=1
Where do these two lines intersect?
Let's add the two equations.
(x+y)+(x-y)=5+1
x+y+x-y=6
2x=6
x=6/2=3
x+y=5
3+y=5
y=5-3=2
(3,2) is the point of intersection of the given lines.
Example 2:
2x+3y=14
5x-y=1
Where do the two lines cut?
2x+3y+5x-y=14+1
7x+2y=15
This isn't working.
Again, let's try differently.
2x+3y=14
5x-y=1
Let's multiply both sides of this equation by 3.
15x-3y=3
Adding the two equations,
2x+3y+15x-3y=14+3
17x=17
x=17/17=1
5x-y=1
5(1)-y=1
5-y=1
-y=1-5
-y=-4
y=4
(1,4) is the point of intersection of the given lines.
Example 3:
2x+5y+29=0
3x+2y+16=0
Let's multiply the first equation by 2 and the second equation by 5.
4x+10y+58=0
15x+10y+80=0
Subtracting the second equation from the first one,
(4x+10y+58)-(15x+10y+80)=0
4x+10y+58-15x-10y-80=0
4x-15x+58-80=0
-11x-22=0
-11x=22
x==22/-11=-22/11=-2
2x+5y+29=0
2(-2)+5y+29=0
-4+5y+29=0
5y+25=0
5y=-25
y=-25/5=-5
(-2,-5) is the point of intersection of the given lines.
Example 4:
2x+y=5
4x+2y=9
Multiplying the first equation by 2,
4x+2y=10
4x+2y=9
Subtracting the second equation from the first one,
(4x+2y)-(4x+2y)=10-9
4x+2y-4x-2y=1
0=-1
This doesn't make sense.
They don't intersect.
THEY ARE PARALLEL.
2x+y=5
y=-2x+5⇒slope = -2
4x+2y=9
2y=-4x+9
y=(-4x+9)/2
y=(-4x/2)+(9/2)
y=(-4/2)x+(9/2)
y=-2x+(9/2)⇒slope = -2
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